1.

Factorise 27a3 + b3 + 8c3 – 18abc using identity

Answer»

27a3 + b3 + 8c3 – 18abc 

= (3a)3 + (b)3 + (2c)3 – 3(3a) (b) (2c) 

= (3a + b + 2c) (9a2 + b2 + 4c2 – 3ab – 2be – 6ca)



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