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Factorise : `27x^(3)+8y^(3)+8z^(3)-36xyz` |
Answer» We can write it `(3x)^(3)+(2y)^(3)+(2z)^(3)-3xx3x xx2yxx2z` `=a^(3)+b^(3)+c^(3)-3abc " " ("where" a=3x,b=2y,c=2z)` `=(3x+2y+2z)(9x^(2)+4y^(2)+4z^(2)-5xy-4yz-6zx)` |
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