1.

Factorise.

Answer»

no

4p^2 - 9p^2(2p)^2 - (3p)^2[a^2 - b^2 = (a+b)(a-b)]=>(2p+3p)(2p-3p)

using a^-b^=(a-b)(a+b)=(4p-9p)(4p+9q)



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