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Factorise 4a2 + b2 + c2 – 4ab + 2bc – 4ca using identity. |
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Answer» 4a2 + b2 + c2 – 4ab + 2bc – 4ca = (2a)2 + (- b)2 + (- c)2 + 2(2a) (- b) + 2 (- b) (- c) + 2(- c) (2a) = (2a – b – c)2 = (2a – b – c) (2a – b – c) |
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