1.

Factorise : 63a^2-112b^2

Answer» =7(9a^2-16b^2) taking out 7 common=7[(3a)^2-(4b)^2] 3a whole sqaure minus 4b whole sqaure=7[(3a-4b)(3a+4b)] using a^2 - b^2 =(a-b)(a+b) identity


Discussion

No Comment Found