1.

Factorise using appropriate identities : 4y2 – 4y + 1

Answer»

4y2 – 4y + 1 

= (2y)2 – 2 (2y) (1) + (1)2 

[∵ (x -y)2 = x2 – 2xy + y2

= (2y -1)2 = (2y – 1) (2y-1)



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