1.

factorise.x^12-y^12-z^12

Answer»

x12–y12=x6 × 2–y6 × 2= (x6)2– (y6)2

= (x6–y6) (x6+y6)

= ((x3)2– (y3)2) ((x2)3+ (y2)3)

= (x3–y3) (x3+y3) (x2+y2) ((x)2–x2y2+ (y2)2)

= (x–y) (x2+xy+y2) (x+y) (x2–xy+y2)(x2+y2) (x4–x2y2+y4)

do the same for z^12

simran Singh your solution is wrong.

how?

extend it with z^12

x^12–y^12-z^12=x^6 × 2–y^6 × 2 -z^6×2= (x^6×2)– (y^6×2) -(z^6×2)

= (x6–y6) (x6+y6) -(z^6)

= ((x3)2– (y3)2) ((x2)3+ (y2)3)

= (x3–y3) (x3+y3) (x2+y2) ((x)2–x2y2+ (y2)2)

= (x–y) (x2+xy+y2) (x+y) (x2–xy+y2)(x2+y2) (x4–x2y2+y4)



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