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factorise.x^12-y^12-z^12 |
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Answer» x12–y12=x6 × 2–y6 × 2= (x6)2– (y6)2 = (x6–y6) (x6+y6) = ((x3)2– (y3)2) ((x2)3+ (y2)3) = (x3–y3) (x3+y3) (x2+y2) ((x)2–x2y2+ (y2)2) = (x–y) (x2+xy+y2) (x+y) (x2–xy+y2)(x2+y2) (x4–x2y2+y4) do the same for z^12 simran Singh your solution is wrong. how? extend it with z^12 x^12–y^12-z^12=x^6 × 2–y^6 × 2 -z^6×2= (x^6×2)– (y^6×2) -(z^6×2) = (x6–y6) (x6+y6) -(z^6) = ((x3)2– (y3)2) ((x2)3+ (y2)3) = (x3–y3) (x3+y3) (x2+y2) ((x)2–x2y2+ (y2)2) = (x–y) (x2+xy+y2) (x+y) (x2–xy+y2)(x2+y2) (x4–x2y2+y4) |
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