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Factorise `x^(2)-6x-y^(2)+9`. |
Answer» Given expression : `x^(2)-6x-y^(2)+9` Here, `x^(2)-6x+9` is perfect square. `therefore` By shifting the position of terms `x^(2)-6x-y^(2)+9=(x^(2)-6x+9)-y^(2)` `=(x-3)^(2)-(y)^(2) [because x^(2)-6x+9=(x)^(2)-2(x)(3)+(3)^(2)]` =(x-3+y)(x-3-y)=(x+y-3)(x-y-3) |
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