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Factorise x^2+(x+1)^2=613

Answer» \underline{\large\bf{\mathfrak{Hello!}}}

= > {x}^{2} + {(x + 1)}^{2} = 613 \\ = > {x}^{2} + {x}^{2} + 2x + 1 = 613 \\ = > 2 {x}^{2} + 2 x + 1 - 613 = 0 \\ = > 2 {x}^{2} + 2x - 612 = 0 \\ = > 2( {x}^{2} + 2 - 306) = 0 \\ = > {x}^{2} + 2 - 306 = 0 \\ = > {x}^{2} + 18x - 17x - 306 = 0 \\ = > x(x + 18) - 17(x + 18) = 0 \\ = > (x + 18)(x - 17) = 0 \\ \\ = > x = - 18 \\ \: \: \: \: \: \: \: \: x = 17

\boxed{x = -18 \: or \: 17}

\bf{\mathfrak{Hope \: this \: helps...:)}}


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