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Factorise x^3-9x^2-x+105 |
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Answer» Check out the solution:-x^3-9x^2-x+105Factors of constant number (105) are: 1,-1,5,-5,7,-7 ,21,-21,105,-105By hit and trial method we foundThat p(7) is giving 0p(x)=0p(7)=0x-7=0So,( x-7) is one factorNow divide (x-7) from x^3-9x^2-x+105We get x^2-2x+15Now a factorise it all three are tha factors including(x-7)I have done it short. But hope it u will understand. TOMORROW IS MY SST EXAM?? I don\'t know |
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