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Factorise: z2 +12z +27 |
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Answer» First find the two numbers whose sum =12 and product = 27 Clearly, the numbers are 9 and 3 ∴ we get, z2 +12z + 27 = z2 + 9z + 3z + 27 = z (z+9) + 3(z+9) = (z+3) (z+9) |
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