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Factorize:27x3 − y3 – z3 – 9xyz |
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Answer» 27x3 − y3 – z3 – 9xyz = (3x)3 − y3 – z3 – 3(3xyz) [a3 + b3 + c3 −3abc = (a + b + c)(a2+b2+c2−ab−bc−ca)] Here a = 3x, b = -y and c = -z = (3x – y – z){ (3x)2 + (- y)2 + (– z)2 + 3xy – yz + 3xz)} = (3x – y – z){ 9x2 + y2 + z2 + 3xy – yz + 3xz)} |
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