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Factorize -X3+6x2-3x-10 |
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Answer» \(-x^3+6x^2-3x-10\) \(\because x=-1\) is a zero of this function. Therefore \((x+1)\) is a factor of it. Now, \(-x^3+6x^2-3x-10\) \(=(x+1)(-x^2+7x-10)\) \(=(x+1)(-x^2+2x+5x-10)\) \(=(x+1)(-x(x-2)+5(x-2))\) \(=(x+1)(x-2)(-x+5)\) \(=-(x+1)(x-2)(x-5)\) |
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