Farhan has received 9 gifts from 9 different people. In how many ways can Farhan receives the gifts such that no one gives him real gifts?(a) 133496(b) 326654(c) 218744(d) 745331I have been asked this question by my school teacher while I was bunking the class.Asked question is from Counting topic in division Counting of Discrete Mathematics

Farhan has received 9 gifts from 9 different people. In how many ways

1.	Farhan has received 9 gifts from 9 different people. In how many ways can Farhan receives the gifts such that no one gives him real gifts?(a) 133496(b) 326654(c) 218744(d) 745331I have been asked this question by my school teacher while I was bunking the class.Asked question is from Counting topic in division Counting of Discrete Mathematics
Answer» Correct choice is (a) 133496 The BEST explanation: By the derangements formula, the NUMBER of possible derangements should be 9!(\(\frac{1}{0!} – \frac{1}{1!} + … – \frac{1}{9!}\)) = 133496. Hence, there are a total of ways to GIVE the gifts to him such that no one distributes the real gifts.

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