`Fe^(2+)` does not give prussian blue colour with `K_4[Fe((CN)_6]`, but on its reaction with (X), prussian blue colour appears with the reagent (X) is :A. `MnO_4^(-)//H^+`B. `H_2SO_4`C. `NH_3`D. All true

`Fe^(2+)` does not give prussian blue colour with `K_4[Fe((CN)_6]`, bu

1.	`Fe^(2+)` does not give prussian blue colour with `K_4[Fe((CN)_6]`, but on its reaction with (X), prussian blue colour appears with the reagent (X) is :A. `MnO_4^(-)//H^+`B. `H_2SO_4`C. `NH_3`D. All true
Answer» Correct Answer - A `MnO_4 H^(+) to[O] : Fe^(2+)overset([O])toFe^(3+)+[Fe(CN)_6]^(4-)to Fe_4[Fe(CN)_6]_3`

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`Fe^(2+)` does not give prussian blue colour with `K_4[Fe((CN)_6]`, but on its reaction with (X), prussian blue colour appears with the reagent (X) is :A. `MnO_4^(-)//H^+`B. `H_2SO_4`C. `NH_3`D. All true

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