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`[Fe(H_(2)O)_(5)NO]^(2+)` is a complex formed in the brown ring test for `NO_(3)^(-)` ion. In this complex.A. NO transfers its electron to `Fe^(2+)` so that we have iron as `Fe(I)` and NO as `NO_^(+)`B. There are three unpaired electron so that its magnetic moment is 3.87 B.M.C. The colour is due to charge transferD. All the above statements are correct. |
Answer» `HgI_(2)overset(Delta)(rarr) Hg_ I_(2) ("violet vapours")` `NO rarr NO^(+) + e^(-)`, `{:(Fe^(2+) ,+,e^(-),rarr,Fe^(+)),((3d^(6)),,,,(3d^(7))),("4 unpaired "e^(-),,,,"3 unpaired "e^(-)):}` `mu` for `Fe^(+) = sqrt(n(n+2))= sqrt(3 xx 5)` BM `= sqrt(15) BM =3.87 BM` |
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