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InterviewSolution
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Fifty seeds were selected at random from each 5 bags of seeds and were kept under standardised conditions favourable to germination . After 20 days , the number of seeds which had germinated in each collection were counted and recorded as follows : What is the probability of germination of (i) more than 40 seeds from a bag ? (ii) 49 seeds from a bag ? (iii) more than 35 seeds from a bag ? |
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Answer» Total number of bags = 5 . (i) Let `E_(1)` be the event of germination of more than 40 seeds from a bag . Then , P (germination of more than 40 seeds from a bag) `= P (E_(1))` `= ("number of bags from which more than 40 seeds germinate")/("total number of bags")` `(3)/(5) = 0.6`. [There are 3 bags from which more than 40 seeds germinate.] (ii) Let `E_2` be the event of germination of 49 seeds . Then , P (germination of 49 seeds from a bag) `= P (E_(2))` = `("number of bags from which 49 seeds germinate")/("total number of bags")` `= (0)/(5) = 0`. [Clearly seeds from none of the given bags contain 49 germinated seeds.] (iii) Let `E_(3)` be the event of germination of more than 35 seeds from a bag . Then , P(germination of more than 35 seeds from a bag) `P(E_(3))` `= ("number of bags from which more than 35 seeds germinate")/("total number of bags")` `= (5)/(5) = 1`. [Seeds from each of the five given bags contain more than 35 germinated seeds.] |
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