1.

Fig. 7. 187 (a) shows a system of two blocks of masses m and M (gt m) placed on a surface , there is no friction between the blocks and the surface . A force F is applied to the system as shown resulting in the motion of the system . Fig. 7.187(b) also shows a system of blocks of masses m and M . Masses m and M have , respectively , the same values as in Fig . 7.187 (a) . There is no friction between the lower block and the surface on which the system is placed but friction is present at the constant of the two blocks . A force F, having the same value as in Fig. 7.187 (a) , is applied to the lower block resulting in the motion of the system such that both blocks move together with a common acceleration . Match Column-I and II.

Answer»


Solution :
(a) `"" a = ((F)/(M = m))`
Force on M
`N = m xx a = (mF)/(M + m)`
`a = (F)/(M + m)`
(B) Force on m = ` m xx a = ((mF)/(M + m))`

(c) If F is applied on m TOWARDS RIGHT

`a = ((F)/(M + m))`
(d) `""a = ((F)/(M + m))`
Force on m , f = ma = `((mF)/(M + m))`


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