InterviewSolution
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Fig., below, gives a speed- time graph of a particle in motion along a constant direction. Three equal intervals of time are shown. In which interval is the average acceleration greatest in magnitude? Choosing the positive direction as the constant direction of the motion. give the sign of 'v' and 'a' in the three intervals. what are the acceleration at the points A,B,C and D? |
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Answer» (i) We know that the magnitude of the slope of (v - t) graph in a small interval gives the magnitude of the average acceleration of the particle. It is clear from the gives figure that the magnitude of the slope is greatest in (2) and the least in (3). Hence, the magnitude of average acceleration is the greatest in the interval (2) and least in the interval (3). (ii) It is clear from the figure that average speed is greatest in the interval (3) and the least in the interval (1). (iii) The speed v is positive in all the three intervals. Further, in interval (1), the slope of (v - t) graph is parallel to the time- axis, hence, a is zero in this interval. (iv) At points A, B, C and D (v - t) graph is parallel to time-axis Therefore, 'a' is zero at all the four points. |
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