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Figure 6.19 shows the p-T graphs for a fixed mass of an ideal gas at volumes V_1 and V_2.Can it be concluded from the graphs that V_1 is greater than V_2? |
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Answer» Solution :`pV=nRT=m/M RT` or, `p=(mR)/(MV)T`[ M=molecular WEIGHTS] So p-T GRAPHS are STRAIGHT lines PASSING through the origin,for any fixed V . The slope `(mR)/(MV)` is smaller for a greater value of V. In fig.6.19 the slope for `V_1` is smaller than that for `V_2`. So, `V_1 gt V_2`
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