Figure given below shows the displace show ment versus time graph for two particles A and B executing simple harmonic motions. Find the ratio of their maximum velocities,

Figure given below shows the displace show ment versus time graph for

1.	Figure given below shows the displace show ment versus time graph for two particles A and B executing simple harmonic motions. Find the ratio of their maximum velocities,
Answer» Solution :For A, time period `T_(A)` = 16s (Distance between two adjacent crets) for B, time period `T_(B) = (26-2) = 24s` [LENGTH between the CREST and trough SHOWN = 20s-8s 12s] Also, amplitudes `a_(A) = 10cm, a_(B) = 5cm` Ratio of maximum velocities `(V_(A))/(V_(B))= (a_(A)omega_(A))/(a_(B)omega_(B))= (a_(A)T_(B))/(a_(B)T_(A))= (10 xx 24)/(5 xx 16)= (3)/(1)`