1.

Figure represents a part of closed circuit. What is the potential differnce between points A and B?

Answer» Potential difference across `2 Omega = 2 xx 2 = 4V`,
Potential differnce across `1 Omega =1 xx 2 = 2 V`.
Given the e.m.f. of the cell is 3 V. Let the positive electrode of cell be + 3 V and - ve electrode of cell at 0V. Therefore potential of `A = 4+ 3= 7V` : Potential of `B =- 2V`, as current is flowing from negative terminal of cell to point B, hence B is at lower potential . Therefore potential differnce between A and B = ` 7 -( -2 )= 9V` .


Discussion

No Comment Found

Related InterviewSolutions