InterviewSolution
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InterviewSolution
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Figure shown two pulley arrangments for lifting a mass `m` . In case-1, the mass is lifting by attaching a mass 2m while in case-2 the mass is lifted by pulling the other end with a downward force `F=2mg` . If `a_(a)` and `a_(b)` are the accelerations of the two masses then (Assumme string is massless and pulley is ideal). A. `a_(a)=a_(b)`B. `a_(a)=a_(b)/(2)`C. `a_(a)=a_(b)/(3)`D. `a_(a)=2a_(b)` |
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Answer» Correct Answer - C In case-1, the acceleration of the system `a_(a)=((2m-m)/(2m+m))g=(g)/(3)` In case-2, the acceleration of the system `a_(a)=((2m-m)/(2m+m))g=(g)/(3)=g` So, `a_(a)=a_(b)//3` . |
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