Figure shown two pulley arrangments for lifting a mass `m` . In case-1, the mass is lifting by attaching a mass 2m while in case-2 the mass is lifted by pulling the other end with a downward force `F=2mg` . If `a_(a)` and `a_(b)` are the accelerations of the two masses then (Assumme string is massless and pulley is ideal). A. `f_(a)=f_(b)`B. `f_(a)=f_(b)//2`C. `f_(a)=f_(b)//3`D. `f_(a)=2f_(b)`

Figure shown two pulley arrangments for lifting a mass `m` . In case-1

1.	Figure shown two pulley arrangments for lifting a mass `m` . In case-1, the mass is lifting by attaching a mass 2m while in case-2 the mass is lifted by pulling the other end with a downward force `F=2mg` . If `a_(a)` and `a_(b)` are the accelerations of the two masses then (Assumme string is massless and pulley is ideal). A. `f_(a)=f_(b)`B. `f_(a)=f_(b)//2`C. `f_(a)=f_(b)//3`D. `f_(a)=2f_(b)`
Answer» Correct Answer - C `f_(a)=((2m-m)/(2m+m))g=g/3` `f_(b)=(2mg-mg)/m=g` So, `f_(a)=f_(b)//3`

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