Figure shows a 5 kg ladder hanging from a string that is connected with a ceiling and is having a spring balance connected in between. A boy of mass 25 kg is climbing up the ladder at acceleration `1(m)/(s^2)`. Assuming the spring balance and the string to be massless and the spring to show a constant reading, the reading of thespring balance is: (Take`g=10(m)/(s^2)`)A. `30 kg`B. `32.5 kg`C. `35 kg`D. `37.5 kg`

Figure shows a 5 kg ladder hanging from a string that is connected wi

1.	Figure shows a 5 kg ladder hanging from a string that is connected with a ceiling and is having a spring balance connected in between. A boy of mass 25 kg is climbing up the ladder at acceleration `1(m)/(s^2)`. Assuming the spring balance and the string to be massless and the spring to show a constant reading, the reading of thespring balance is: (Take`g=10(m)/(s^2)`)A. `30 kg`B. `32.5 kg`C. `35 kg`D. `37.5 kg`
Answer» Correct Answer - B If reading of spring balance is T, then applying NLM on (man+ ladder) system `T-(25+5) g =25a` `T-30 g=25a rArr T-300=25(1) rArr T=325 N=32.5 kg`.

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