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Figure shows a concave mirror with its pole at (0,0) and principal axis along x axis. There is a point object at (-40 cm, 1cm) Then the position of image (-40,1) |
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Answer» SOLUTION :According to SIGN convention, `u=-40cm implies h_1=1cm implies f=-5cm` `implies 1/v+1/u=1/f implies 1/v+1/(-40)=1/(-5) implies V=(-40)/7 cm`, `h_2/h_1=(-v)/u, h_2=(-v)/u times H= (-(-40/7) times 1)/(-40)=-1/7 cm` `therefore` The POSITION of IMAGE is `((-40)/7 cm,-1/7 cm)` |
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