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Figure shows a concave mirror with its pole at (0,0) and principal axis along x axis. There is a point object at (-40 cm, 1cm) Then the position of image (-40,1) |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to <a href="https://interviewquestions.tuteehub.com/tag/sign-1207134" style="font-weight:bold;" target="_blank" title="Click to know more about SIGN">SIGN</a> convention, <br/> `u=-40cm implies h_1=1cm implies f=-5cm` <br/> `implies 1/v+1/u=1/f implies 1/v+1/(-40)=1/(-5) implies V=(-40)/7 cm`, <br/> `h_2/h_1=(-v)/u, h_2=(-v)/u times <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>= (-(-40/7) times 1)/(-40)=-1/7 cm` <br/>`therefore` The <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/image-11684" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGE">IMAGE</a> is `((-40)/7 cm,-1/7 cm)`</body></html> | |