Figure shows a fixed wedge on which two blocks of masses `2 kg` and `3 kg` are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.

Figure shows a fixed wedge on which two blocks of masses `2 kg` and `3

1.	Figure shows a fixed wedge on which two blocks of masses `2 kg` and `3 kg` are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.
Answer» Block `A` slides with aceleration `g//2` and block `B` slides wth acceleration `sqrt(3)g//2`. Now the acceleration of centre of mass of the system of blocks `A` and `B` can be given both in `x` and in `y` directions as: `a_(x)=(3xx(sqrt3g)/2cos60^(@)-2xxg/2cos30^(@))/5=sqrt(3g)/20` and `a_(y)=(3xx(sqrt(3)g)/2sin60^(@)+2xxg/2sin30^(@))/5=(11g)/20` Thus acceleration of the centre of mass of the system is given as `a_(CM)=sqrt(a_(x)^(2)+a_(r)^(2)=sqrt((sqrt(3))/(20)6+((11g)/(20)^(2))=sqrt(31)/1g`

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Figure shows a fixed wedge on which two blocks of masses `2 kg` and `3 kg` are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.

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