Figure shows a meter bridge wire AC with a uniform cross-section. The length of wire AC is 100 cm. X is a standard resistor of 4 Ω and Y is a coil. When Y is immersed in melting ice the null point is at 40 cm from point A. When the coil Y is heated to 100∘ C, a 12 Ω resistor has to be connected in parallel with Y in order to keep the bridge balanced at the same point. The temperature coefficient of resistance of the coil Y is x×10−2. The value of x is

Figure shows a meter bridge wire AC with a uniform cross-section. The

1.	Figure shows a meter bridge wire AC with a uniform cross-section. The length of wire AC is 100 cm. X is a standard resistor of 4 Ω and Y is a coil. When Y is immersed in melting ice the null point is at 40 cm from point A. When the coil Y is heated to 100∘ C, a 12 Ω resistor has to be connected in parallel with Y in order to keep the bridge balanced at the same point. The temperature coefficient of resistance of the coil Y is x×10−2. The value of x is
Answer» Figure shows a meter bridge wire $A C$ with a uniform cross-section. The length of wire $A C$ is $100 cm$ . $X$ is a standard resistor of $4 Ω$ and $Y$ is a coil. When $Y$ is immersed in melting ice the null point is at $40 cm$ from point $A$ . When the coil $Y$ is heated to $100^{\circ} C$ , a $12 Ω$ resistor has to be connected in parallel with $Y$ in order to keep the bridge balanced at the same point. The temperature coefficient of resistance of the coil $Y$ is $x \times 10^{- 2}$ . The value of $x$ is

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