Figure shows a potentiometer arrangemeter with `R_(AB)=10 Omega` and rheostat of variable resistance d. For `x=0` null deflection point is found at `20 cm` from `A`. For unknown value of `x` null deflection point was at `30 cm` from `A`, then the value of x is A. `10Omega`B. `5Omega`C. `2Omega`D. `1Omega`

Figure shows a potentiometer arrangemeter with `R_(AB)=10 Omega` and r

1.	Figure shows a potentiometer arrangemeter with `R_(AB)=10 Omega` and rheostat of variable resistance d. For `x=0` null deflection point is found at `20 cm` from `A`. For unknown value of `x` null deflection point was at `30 cm` from `A`, then the value of x is A. `10Omega`B. `5Omega`C. `2Omega`D. `1Omega`
Answer» Correct Answer - B `E_0=V_(AC)=(i)_(AC)(R)_(AC)` `=(E/10)(10/1xx0.2)` `=E/5` In second case, `E_0=((E)/(10+x)) ((10)/1xx0.3)`……….ii Solving eqn i and ii we get `x=5Omega`

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