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Figure shows a potentiometer with a cell of 2.0 V and internal resistance 0.40 Omegamaintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf of 1.02 V (for every moderate currents upto a few mA) gives a balance point at 67.3 cm length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 Omegais put in series with it, which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf epsi and the balance point found similarly, turns out to be at 82.3 cm length of the wire. What purpose does the high resistance of 600 K Omega have ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :to <a href="https://interviewquestions.tuteehub.com/tag/reduce-1181332" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCE">REDUCE</a> <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> through the galvanometer when the <a href="https://interviewquestions.tuteehub.com/tag/movable-1104539" style="font-weight:bold;" target="_blank" title="Click to know more about MOVABLE">MOVABLE</a> contact is <a href="https://interviewquestions.tuteehub.com/tag/far-459491" style="font-weight:bold;" target="_blank" title="Click to know more about FAR">FAR</a> from the balance point.</body></html>


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