Figure shows a rectangular current-carrying loop placed `2cm` away from a long, straight, current carrying conductor. What is the direction and magnitude of the net force acting on the loop?

Figure shows a rectangular current-carrying loop placed `2cm` away fro

1.	Figure shows a rectangular current-carrying loop placed `2cm` away from a long, straight, current carrying conductor. What is the direction and magnitude of the net force acting on the loop?
Answer» Here, `I_1=15A, I_2=25A`, `r_1=2xx10^-2m, r_2=(2+10)xx10^-2m` Force on BC, `F_1=(mu_0)/(4pi)(2I_1I_2)/(r_1)xxl enght BC` `=10^-7xx(2xx15xx25)/((2xx10^-2))xx(25xx10^-2)` `=9375xx10^-4N` (repulsive, away from XY) Force on DA, `F_2=(mu_0)/(4pi)(2I_1I_2)/(r_2)xx l eng th DA` `=10^-7xx(2xx15xx25)/((2+10)xx10^-2)xx25xx10^-2` `=15625xx10^-4N` (attractive towards XY) Net force on the loop `F=F_1-F_2` `=(9375-15625)xx10^-4` `=7*8175xx10^-4N`

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Figure shows a rectangular current-carrying loop placed `2cm` away from a long, straight, current carrying conductor. What is the direction and magnitude of the net force acting on the loop?

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