1.

Figure shows a snapshotof a sinusoidal travelling wave taken at t= 0.3 s.The wavelength is 7.5 cm and the amplitude is 2 cm. If the crest P was at x= 0at t = 0, write theequation of travelling wave. ,

Answer»


Solution :Given, `A = 2 cm, LAMBDA=7.5 cm`
`:. k=(2pi)/(lambda)=0.84 cm^(-1)`
The wave has travelled a distance of `1.2 cm` in `0.3 s`. Hence, speed of the wave,
`v=(1.2)/(0.3) = 4 cm//s`
`:.` ANGULAR frequency `omega=(v)/(k)=3.36 rad//s`
Since the wave is travelling along positive X-directionand crest (maximum displacement) is at `x = 0` at `t= 0` , we can write the wave equation as
`y(x, t)=A cos (kx -OMEGAT)`
or `y(x, t)= A cos (omegat -kx)`as`cos(- theta)= cos theta`
Therefore, the desired equation is
`y(x, t) = (2 cm) cos [(0.84 cm^(-1) x - (3.36 rad//s)t] cm`


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