1.

Figure shows the graph of velocity versus displacement of a particle executing simple harmonic motion. Find the period of oscillation of the particle

Answer»

SOLUTION :`x_("max")= A= 10cm` and
`v_("max")= omegaA= 0.6 MS^(-1)`
`:. Omega= (v_("max"))/(v_("max"))= (6 xx 10^(-1))/(10xx10^(-2))= 6rads^(-1)`
`:. T= (2PI)/(omega)= (2pi)/(6)= (PI)/(3) "sec"`


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