Saved Bookmarks
| 1. |
Figure shows the graph of velocity versus displacement of a particle executing simple harmonic motion. Find the period of oscillation of the particle |
|
Answer» SOLUTION :`x_("max")= A= 10cm` and `v_("max")= omegaA= 0.6 MS^(-1)` `:. Omega= (v_("max"))/(v_("max"))= (6 xx 10^(-1))/(10xx10^(-2))= 6rads^(-1)` `:. T= (2PI)/(omega)= (2pi)/(6)= (PI)/(3) "sec"` |
|