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Figure shows the system is at rest initially with `x = 0`, A man and a woman both are initially at the extreme carrier of the platform. The man and the woman start to move towards each other. Obtain an expression for the displacement `s` of the platform when the two meet in terms of the displacement `x_1` of the man relative to the platform. ` |
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Answer» As no external force is acting on the system the diplacemnte of the centre of mass should be zero. Let the displacement of the platform toward right be `s`. `/_vecx_(1)=/_vecx_(1,p)+/_vecv_(p)=(-x_(1)+s)` `/_vecx_(2)=/_vecx_(2,p)+/_vecx_(p)=(l-x_(1)+s)` Hence, `0=(m_(1)(-x_(1)+s)+m_(2)(l-x_(1)+s)+m_(0)s)/(m_(1)+m_(2)+m_(3))` `s(m_(1)+m_(2)+m_(0))-m_(1)x_(1)+m_(2)(l-x_(1))=0` `s=(m_(1)x_(1)-m_(2)(l-x_(1)))/(m_(1)+m_(2)+m_(0))` |
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