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Figure shows the variation of intensity of magnetisation vecM versus the applied magnetic field intensity vecH for two materials A and B: (a) Identify the materials A and B. (b) Why does the material B, have a larger susceptibility than A for a given field at constant temperature ?

Answer» <html><body><p></p>Solution :(a) Material A is <a href="https://interviewquestions.tuteehub.com/tag/diamagnetic-950823" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMAGNETIC">DIAMAGNETIC</a> because its magnetisation is negative <br/>Material B is <a href="https://interviewquestions.tuteehub.com/tag/paramagnetic-2210688" style="font-weight:bold;" target="_blank" title="Click to know more about PARAMAGNETIC">PARAMAGNETIC</a> having positive magnetisation . <br/>(b) Magnetic susceptibility ` x = M/H` and its <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> is given by slope of M - H <a href="https://interviewquestions.tuteehub.com/tag/curve-941741" style="font-weight:bold;" target="_blank" title="Click to know more about CURVE">CURVE</a>. As slope of curve for material B is greater, hence B has a large susceptibility than A for a given <a href="https://interviewquestions.tuteehub.com/tag/field-987291" style="font-weight:bold;" target="_blank" title="Click to know more about FIELD">FIELD</a> at constant temperature.</body></html>


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