InterviewSolution
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InterviewSolution
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Figure, shows the variation of potential energy `(U)` of 2 mol of Argon gas with its density in a cyclic process `ABCA`. The gas was initiallly in the state `A` whose pressure and temperature are `P_(A)=2 atm, T_(A)=300K`, respectively. It is also stated the path `AB` is a rectangular hyperbola and the internal energy of the gas at state `C` is `3000r`. Based on the above information answer the following question `:` A. The process `AB` is isobaric, `BC` is adiabatic and `CA` is isochoric.B. The pocess is `AB` is adiabatic, `BC` is isothermal and `CA` is isochoric.C. The process `AB` is isochoric, `BC` is isothermal and `CA` is isobaricD. The process `AB` is isochoric, `BC` is isothermal and `CA` is isochoric |
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Answer» Correct Answer - D Since `AB` is rectangular hyperbola, therefore, `:. U rho=` Constant `implies n C_(v)T(PM)/(RT)=C` `implies P=` Constant `:. AB rarr` isobaric ` BC rarr` isothermal as `U` is constant `CA rarr` isochoric as `rho` is constant |
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