1.

Figure shows two processes X and Y on a ideal gas system. Let ∆QX and ∆QY be the heat given to the system in processes X and Y respectively, then(a) ∆QX = ∆QY(b) ∆QX > ∆QY(c) ∆QX < ∆QY(d) ∆QX ≤ ∆QY

Answer»

Answer is : (b) ∆QX > ∆QY

∆UX = ∆UY (For cyclic process)

So, ∆WX = ∆QX and ∆WY > ∆QY

As from figure, ∆WX > ∆WY

So, ∆QX > ∆QY


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