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Fill in the blank `""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n`A. `._(56)^(141)Sr`B. `._(56)^(141)La`C. `._(56)^(141)Ba`D. `._(56)^(141)Cs` |
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Answer» Correct Answer - c Let symbol of element is `._(Z)^(M)P`. 92 = Z + 36 `:.` Z = 56 235 + 1 M + 92 + 3 M = 141 Thus, the element P will be `._(56)^(141)Ba` |
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