1.

Fill in the blank `""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n`A. `._(56)^(141)Sr`B. `._(56)^(141)La`C. `._(56)^(141)Ba`D. `._(56)^(141)Cs`

Answer» Correct Answer - c
Let symbol of element is `._(Z)^(M)P`.
92 = Z + 36
`:.` Z = 56
235 + 1 M + 92 + 3
M = 141
Thus, the element P will be `._(56)^(141)Ba`


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