1.

Fill in the blanks.(i) \(7\frac{1}{2}\%\) of Rs.1200 = ……..(ii) 240 mL is……% of 3 L.(iii) If x% of 35 is 42, then x = ……..(iv) \(\frac{12}{5}\) = ........%(v) 120 = (……)% of 80.

Answer»

(i) 90

\(7\frac{1}{2}\%\) of Rs.1200 = (15/2) % of Rs.1200

= 15/2 × 1/100 × 1200 

= 15/2 × 12 

= 90 

∴ Rs.90

(ii) 8

240 mL = (240/1000) L

Now,

Percentage = (240/1000 × 1/3 × 100) %

= (240/10 × 1/3) % 

= (80/10) % 

= 8%

(iii) 120 

X% of 35 = 42 

⇒ 35 × X/100 = 42 

⇒ 35X/100 = 42 

⇒ X = 42 × 100/35 

⇒ X = 6 × 100/5 

⇒ X = 120

(iv) 240 

12/5 = (12/5 × 100) % 

= (12 × 20) % 

= 240%

(v) 150 

Let the number = Z 

∴ 120 = Z% of 80 

⇒ 120 = 80 × Z/100 

⇒ Z = 120 × 100/80 

⇒ Z = 120 × 5/4 

⇒ Z = 150



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