Fill in the blanks with appropriate choice. Bond ordr of N_(2)^(+) is ul(" "P)while that of N_(2) is ul(" "Q). Bond order of O_(2)^(+) is ul(" "R) while that of O_(2) is ul(" "S). N - N bond distance ul(" "T) when N_(2) changes to N_(2)^(+)and when O_(2) changes to O_(2)^(+) , the O - O bond distance ul(" "U).

Fill in the blanks with appropriate choice. Bond ordr of N_(2)^(+) is

1.	Fill in the blanks with appropriate choice. Bond ordr of N_(2)^(+) is ul(" "P)while that of N_(2) is ul(" "Q). Bond order of O_(2)^(+) is ul(" "R) while that of O_(2) is ul(" "S). N - N bond distance ul(" "T) when N_(2) changes to N_(2)^(+)and when O_(2) changes to O_(2)^(+) , the O - O bond distance ul(" "U).
Answer» `{:(P,Q,R,S,""T,""U),(2,2.5,2.5,1,"INCREASES","decreases"):}` `{:(P,Q,R,S,""T,""U),(2.5,3,2,1.5,"decreases","increases"):}` `{:(P,Q,R,S,""T,""U),(3,2,1.5,1,"increases","decreases"):}` `{:(P,Q,R,S,""T,""U),(2.5,3,2.5,2,"increases","decreases"):}` Solution :`N_(2)^(+) : (SIGMA1S^(2))(sigma^()1S^(2))(sigma2s^(2))(sigma^()2s^(2))(pi 2p_(x)^(2) = pi 2p_(y)^(2))(sigma2p_(z)^(1))` B.O. ` = 1/2 xx (9-4) = 2.5` `N_(2) : B.O. = 1/2 xx (10 - 4) = 3` `O_(2)^(+) : (sigma1s^(2))(sigma^()1s^(2))(sigma2s^(2)) (sigma^()2s^(2))(sigma2p_(z)^(2))(pi 2p_(x)^(2)pi 2p_(y)^(2))(pi^(**)2p_(x)^(1))` B.O. ` = 1/2 xx (10 - 5) = 2.5` ` O_(2) : B.O. = 1/2 xx (10 - 6) = 2` Since `N_(2)^(+)` has lower BOND order than `N_(2)`, bond length of N - N in `N_(2)^(+)` increases. In `O_(2)^(+)`, bond order increases from 2 to`2.5` hence, bond length decreases.