1.

Fill in the blanks with correct inequality sign(>,<,\(\ge\), \(\le\)).(i) 5x < 20 ⇒ x ………. 4 (ii) –3x > 9 ⇒ x ………. –3 (iii) 4x > –16 ⇒ x ………. –4 (iv) –6x ≤ –18 ⇒ x ………. 3 

Answer»

(i) 5x < 20 

⇒ x ……… 4 

As, 5x < 20 

Then, 

Dividing both the sides by 5 

\(\frac{X}{5} <\frac{20}{5}\)

x < 4 

Therefore, 

5x < 20 

⇒ x < 4 

(ii) -3x > 9 

⇒ x ……… -3 

As, -3x > 9 

Then, Dividing both the sides by 

\(\frac{X}{3}> - \big(\frac{9}{3}\big)\)

x > -3

Therefore, 

-3x > 9 ⇒ x > -3 

(iii) 4x > -16 ⇒ x ……… -4 As, 

4x > -16 

Then, Dividing both the sides by 4

\(\frac{X}{4} > - \big(\frac{16}{4}\big)\)

x > -4 

Therefore, 

4x > -16 

⇒ x > -4 

(iv) -6x ≤ -18 

⇒ x ……… 3 

As -6x ≤ -18 

Then, Dividing both the sides by 6

\(\frac{-X}{6} \le \big(\frac{-18}{6}\big)\)

-x \(\le\) -3

Now multiplying by -1 on both sides 

-x(-1) ≤ -3(-1) 

x ≥ 3 (inequality sign reversed) 

Therefore, 

-6x ≤ -18 ⇒ x ≥ 3 


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