1.

Find a cubic polynomial whose zeroes are 1/2, 1 and -3.

Answer»

General form of a cubic polynomial whose zeroes are a, b and c is:

x3 – (a + b + c) x2 + (ab + bc + ca)x – abc …(1)

To Find: Cubic polynomial whose zeroes are 1/2, 1 and -3

Let us say, a = 1/2, b = 1 and c = -3

Putting the values of a, b and c in the equation (1) we get:

= x3 – (1/2 + 1 – 3) x2 + (1/2 – 3 – 3/2)x – (- 3/2)

= x3 – (-3/2) x2 – 4x + 3/2

= 2x3 + 3x2 – 8x + 3

Which is required polynomial.



Discussion

No Comment Found