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Find a cubic polynomial whose zeroes are 1/2 , 1 and –3. |
Answer» If the zeroes of the cubic polynomial are a, b and c then the cubic polynomial can be found as x3 – (a + b + c)x2 + (ab + bc + ca)x – abc ……(1) Let a = 1/2 , b = 1 and c = –3 Substituting the values in (1), we get x3 – ( 1/2 + 1 − 3)x2 + ( 1/2 − 3 − 3/2 )x – ( −3/2 ) ⇒ x3 – ( −3/2 )x2 – 4x + 3/2 ⇒ 2x3 +3x2 – 8x + 3 |
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