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Find a point on \( x \)-axis which is at \( 5 \sqrt{3} \) distance from the point \( (-2,3) \) |
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Answer» Let required point on x- axis is (x, 0). \(\therefore\) Distance between points (x, 0) and (-2, 3) is 5√3. \(\therefore\) \(\sqrt{(-2-x)^2+(3-0)^2}\) = 5√3 ⇒ (2 + x)2 + 9 = 25 x 3 (By squaring both sides) ⇒ (x + 2)2 = 75 - 9 = 66 ⇒ (x + 2) = \(\pm\sqrt{66}\) ⇒ x = -2 \(\pm\sqrt{66}\) Hence required point is (-2\(+\sqrt{66}\), 0) or (-2,\(-\sqrt{66}\), 0) |
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