1.

Find all points of discontinuity of f where f is defined by f(x)={(2x+3,xle2),(2x-3,x>2):}

Answer»

Solution :`f(x)={(x,ifxle1),(5, ifx>1):}}` For `xgt1,f(x)=5` which is a constant FUNCTION and THEREFORE conti nuous. Hence f(x) is continuous at x=2.


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