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Find an equation of the plane containing the point (0,1,1) and perpendicular to the line passing through the points (2,1,0) and (1,−1,0)? |
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Answer» The equation of a plane containing the point (0,1,1) and perpendicular to the line passing through the points (2,1,0) and (1,−1,0) is x - 2y + 2 = 0. If aplane passes through the point(x1, y1, z1), the equation of a plane is represented as A(x - x1)+B(y- y1)+C(z - z1) = 0. |
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