1.

Find an equation of the tangent line to the curve at the given point. y = sec x, (π/6, 2√3/3)

Answer» Find an equation of the tangent line to the curve at the given point.
y = sec x, (π/6, 2√3/3)

The equation of tangent to the curve f(x) at (a , b) can be found by finding the slope of tangent which is f'(a)



Discussion

No Comment Found