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Find an experssion for the acceleration of the particle and hence indicate its direction . |
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Answer» SOLUTION :Acceleration of the particle, `VEC(a) = (d vec(V))/(dt) = R omega(- COS theta hat(i) - sin theta hat(j) ) (d theta)/(dt)` ` = - r omega^(2) (cos theta hat(i) + sin theta hat(j)) " " [ because omega = "constant"]` = `- omega^(2) vec(r )` ` therefore vec(a) and vec(r)` are acted in opposite direction. |
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