Find `angleP` in the figure below. – InterviewSolution

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1.	Find `angleP` in the figure below.
Answer» In `Delta ABC and Delta QRP`, we have `(AB)/(QR)=(3.6)/(7.2)=(1)/(2), (BC)/(RP)=(6)/(12)=(1)/(2) and (CA)/(PQ)=(3sqrt(3))/(6sqrt(3))=(1)/(3)` Thus, `(AB)/(QR)(BC)/(RO)=(CA)/(PQ) ` and so `Delta ABC~Delta QRP` [ by SSS-similarity] `:. angle C= angleP` [ corresponding angles of similar triangles] But, `angle C=180^(@)-(angleA+angleB)=180^(@)-(70^(@)+60^(@))=50^(@)`. `:. angle P=50^(@)`

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