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Find approximate values of the following : 2^(3.02) |
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Answer» SOLUTION :LET `y = 2^x` Then `dy = 2^x IOG 2 dx` `rArr deltay = 2^x Iog 2 deltax` `2^(x+deltax) - 2^x = 2^x` Iog `2 deltax` `rArr 2^(x+deltax) = 2^x + 2^x` Iog `2 deltax` Then `2^(3.02) = 2^3 + 2^3` Iog 2 x 0.02 = 8 + 8 x0.3010 x 0.02 = 8+0.04816=8.04816` |
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